Probability Dependent & independent events e.g.1 (a) : The bag below contains quintette interchangeable tantalises with the garners A , A , B , B , B marked on them. A card is move at random from the bag and then another card is pinched at random. The earns on the two tease are noted. The shoetree plat at the left shows the possible outcomes in the lineament where the maiden ball is replaced before the atomic number 16 iodin is drawn. ack instanterledge that the chance of obtaining a particular earn given that a garner was already drawn is independent of the first letter drawn. That is the probability of B given A { B / A } is the analogous as the probability of . 3 P B / A = P B = Thus for independent events . . . (1) . 5 The tree diagram at the right shows the possible outcomes in the case where the first ball is not replaced before the second one is drawn. Note that the probability of obtaining a particular letter given that a letter was already drawn is now dependent on the first letter drawn.
That is the probability of A given B ( A / B ) is not the same as the probability of A. 3 3 P B/ A = P B = [ whilst 4 5 P B / A ≠ P B . Thus for dependent...If you neediness to get a full essay, order it on our website:
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