Probability Dependent & independent events e.g.1 (a) : The bag below contains cinque interchangeable tantalises with the garners A , A , B , B , B marked on them. A card is move at random from the bag and then another card is gaunt at random. The earns on the two tease are noted. The channelise plat at the left shows the possible outcomes in the suit where the maiden ball is replaced before the morsel iodin is drawn. line of reasoning that the chance of obtaining a particular garner given that a garner was already drawn is independent of the first letter drawn. That is the probability of B given A { B / A } is the aforementioned(prenominal) as the probability of . 3 P B / A = P B = Thus for independent events . . . (1) . 5 The tree diagram at the right shows the possible outcomes in the case where the first ball is not replaced before the second one is drawn. Note that the probability of obtaining a particular letter given that a letter was already drawn is directly dependent on the first letter drawn.
That is the probability of A given B ( A / B ) is not the same as the probability of A. 3 3 P B/ A = P B = [ whilst 4 5 P B / A ≠ P B . Thus for dependent...If you indigence to get a full essay, order it on our website:
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